求∫[(1+arxcosx)/√(1-x2)]dx

求∫[(1+arxcosx)/√(1-x²)]dx
【正确答案】：arcsinx-1/2(arccosx)²+C 分析 ∫[(1+arxcosx)/√(1-x²)]dx =∫[1/√(1-x²)]dx-∫arccosxd(arccosx) =arcsinx-1/2(arccosx)²+C