计算定积分I=∫10xarctanxdx

计算定积分I=∫10xarctanxdx
【正确答案】:I=x2/2 actanx|10-1/2∫10[x2/(1+x2)]dx =π/8-1/2∫10[1-1/(1+x2)dx =π/8-1/2(x-arctanx)|10 =π/4-1/2