求∫[x4/(x2+1)]dx．

求∫[x4/(x2+1)]dx．
【正确答案】：(1/3)x3-x+arctanx+C 分析 ∫[x4/(x2+1)]dx=∫[(x4-1+1)/(x2+1)]dx =∫[x2-1+1/(x2+1)]+dx =(1/3)x3-x+arctanx+C
上一篇：∫x2arctanxdx