设f(x){ex-2,x≥0,e1/x-1,x＜0,求limx→0f(x)

设f(x)
{e^x-2,x≥0,
e^1/x-1,x＜0,
求lim_x→0f(x)
【正确答案】：f(0+0)=lim_x→0+(e^x-2)=-1， f(0-0)=lim_x→0-(e^1/x-1)=-1，所以lim_x→0f(x)=-1．