设随机变量(X，Y)的分布函数F(x，y)=1/π2[π/2+arctan(x/3)][π/2+arctan(y/2)]，则(X，Y)的概率密度为____．
【正确答案】：f(x,y)=6/[π2(9+x2)(4+y2)]
设随机变量(X，Y)的分布函数F(x，y)=1/π2[π/2+arctan(x/3)][π/2+arctan(y/2)]，则(X
- 2024-08-03 22:00:07
- 概率论与数理统计（二）(02197)
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