设X~N(5,9),已知标准正态分布函数值Φ(0.5)=0.6915,为使P{X﹤a)﹤0.6915,则常数a﹤____.
【正确答案】:6.5 。解析:P{X﹤a}=Φ[(a-5)/3]﹤0.6915=Φ(0.5) ∴(a-5)/3﹤0.5.∴a﹤6.5
设X~N(5,9),已知标准正态分布函数值Φ(0.5)=0.6915,为使P{X﹤a)﹤0.6915,则常数a﹤____.
- 2024-07-28 21:10:16
- 概率论与数理统计(经管类)(04183)