求二重积分
∫∫Dsin(x+y)dσ,其中D={(x,y)|0≤x≤π/2,0≤y≤π/2};
【正确答案】:解:∫∫Dsin(x+y)dσ=∫∫Dsin(x+y)dxdy
=∫π/20dx∫π/20sin(x+y)dy
=∫π/20[-cos(x+y)]|π/20dx
=∫π/20[cos-cos(x+π/2)]dx
=∫π/20(cosx+sinx)dx
=(sinx-cosx)|π/20=2
求二重积分 ∫∫Dsin(x+y)dσ,其中D={(x,y)|0≤x≤π/2,0≤y≤π/2};
- 2024-11-07 09:09:43
- 高等数学(经管类)(13125)
- 1