设f(x+y,x-y)=x2-y2,则f(x,y)=()
A、x2-y2
B、x2+y2
C、(x-y)2
D、xy
【正确答案】:D
【题目解析】:多元函数.f(x+y,z-y)=x2-y2=(x+y)(x-y),令u=x+y,υ=x-y,则f(x+y,x-y)=f(u,υ)=u,即f(x,y)=xy.
设f(x+y,x-y)=x2-y2,则f(x,y)=()
- 2024-11-07 09:02:43
- 高等数学(经管类)(13125)