以下是某网络报文记录分析仪监测的一帧完整SV 采样报文(IEC61850 9−2,采样通道顺序:IA1、IA2、IB1、IB1、IC1、IC2、I01、I02、I0、UA、UB、UC、IA、IB、IC)报文,分析该报文,回答以下问题。 01 0C CD 04 01 44 52 47 51 20 26 D0 81 00 A0 14 88 BA 41 44 00 B5 00 00 00 00 60 81 AA 80 01 01 A2 81 A4 30 81 A1 80 0F 54 46 44 32 43 30 33 42 5F 31 38 4D 55 30 31 82 02 09 A7 83 04 00 00 00 01 85 01 01 87 81 80 00 00 01 F4 00 00 00 00 00 13 51 00 00 00 00 00 00 00 14 C1 00 00 00 00 FF FF E3 63 00 00 00 00 FF FF DC 58 00 00 00 00 FF FF EA F6 00 00 00 00 FF FF F2 89 00 00 00 00 FF FF FF 2D 00 00 00 00 FF FF FC 6C 00 00 00 00 00 00 01 D1 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 93 00 00 00 00 00 00 04 A6 00 00 00 00 00 00 01 D4 00 00 00 00 (1)解析其 Destination MAC 和 SourceMAC。 (2)写出该报文的APPID(十六进制)以及APP Length(十进制) (3)该报文的同步状态如何? (4)写出 SV 采样报文的额定延迟时间和IA1有效值为多少。 (5)请问 SV 采样报文各通道的品质是否异常?
["\uff081\uff09Destination MAC\uff1a01-0C-CD-04-01-44\n SourceMAC\uff1a52-47-51-20-26-D0-81\n\uff082\uff09APPID\uff1a0x4144 APP Length\uff1a181\uff0800 B5\uff09\n\uff083\uff09smpSynch\u4e3a01\uff0c\u8be5\u62a5\u6587\u5904\u4e8e\u540c\u6b65\u72b6\u6001\n\uff084\uff09\u989d\u5b9a\u5ef6\u65f6\u4e3a500\uff0cIA1\u4e3a0x00135100=1265920\uff08\u5341\u8fdb\u5236\uff09\n1265920*1mA=1265.920A\uff0c\u6709\u6548\u503c\u4e3a1265.920\/1.414=895.27A\n\uff085\uff09\u54c1\u8d28\u4e3a00 00 00 00\uff0c\u5747\u65e0\u5f02\u5e38\u3002"]