求(1-sin6α-cos6α)/(1-sin4α-cos4α)的值．

求(1-sin⁶α-cos⁶α)/(1-sin⁴α-cos⁴α)的值．
【正确答案】：(1-sin⁶α-cos⁶α/1-sin⁴α-cos⁴α)=[1-(sin²α+cos²α)(sin²α-sin²αcos²α+cos²α)]/[1-(1-2sin²αcos²α)]=[1-(1-3sin²αcos²α)]/[1-(1-2sin²αcos²α)]=3/2