cos(19π/6)+tan(16π/3)的值为()．
A、√3/2
B、-(1/2)+√3/3
C、-[(√3)/2]
D、1/2-(√3)/2
【正确答案】：A
【题目解析】：cos(19π/6)+tan(16π/3)=cos[(18π+π)/6]+tan[(15π+π)/3] =cos(3π+π/6)+tan(5π+π/3) =-cosπ/6+tanπ/3 =-√3/2+√3 =√3/2
cos(19π/6)+tan(16π/3)的值为()．
- 2024-09-16 19:47:05
- 数学（文史类）（高升专）(c0002)